Question

graph linear equation by solving for y first
-2x+3y=-3

Answer 1

Move the variables around for slope intercept form.
y = mx + b

3y = 2x - 3

Then just divide the 3 to the other side

y = (2/3)x - 1

Y-intercept is -1, slope is 2/3

Answer 2

how would you put that in graph

Answer 3

As you can see, because the y-intercept is -1, it will cross the -1 on the y-axis.

As for the slope, which is "m" in the equation "y=mx+b", it's 2/3.

Before you graph the slope, first make sure you have the y-intercept graphed.

Now, to graph the slope, just remember the phrase "rise/run". If 2/3 is the slope, then you start from the y-intercept, and you rise 2, then run 3. In other words, from (0, -1), you go up 2, then to the right 3, and plot a point there.

Now keep repeating the rise/run process from the points you plot and once you've plotted down 2 or 3 points, you should be able to draw a straight line between the points. Now, you have a graph! :)

Answer 4

thank you