Question

Solve for Y.
3x+7y = 6x+1

If anyone could guide me, that would help so much. Thanks

Answer 1

Possible answers:

y=3x+9

y=7x-1/3

y=3x+1/7

y=9x+1/7

Answer 2

You want 7y by itself. So you want to get rid of 3x.
So, (3x + 7y) - 3x = 7y
Now, if you subtract 3x on one side of the equation, then you must do it to the other side of the equation.

(6x + 1) - 3x = ?

Answer 3

I got 7y = 3x+1. Is that incorrect?

Answer 4

No. That is correct. :)
Alright, now you want just y, not 7y.
So what do you think you have to do?

Here's a hint: 7y is a coefficient. So another way of writing 7y is 7 * y.

Answer 5

Would you divide by Y?

Answer 6

Like, put 7/y

Answer 7

Hmm. Well, 7y / y = 7.
Since 7y can be represented as 7 * y.
So 7 * y / y = 7.
Make sense?
You want y, not 7.
So what else do you think you have to do?

Answer 8

Our equation looks like, 7y = 3x + 1.
If that helps. >_>

Answer 9

Divide 7y by 7?

Answer 10

Good! Now if you divide 7 on one side of the equation, then you must do it on the other side of the equation.
Do you see the answer?

Answer 11

3x+1/7? :)

Answer 12

Great! I hope this help. :)

Answer 13

It does! I have one more :)

Answer 14

Do you think you can help?

Answer 15

Alright. :)

Answer 16

5(3ax+y)=8ax, -3y for x

Answer 17

So, -3y = x ?
Sorry, just making sure.

Answer 18

I believe so. My paper didn't have a comma after the 8ax, but Ill assume that's what it is.

Answer 19

There are also some possible answers if this helps:

-8y/-23a

-8y/-7a

-4y/-7a

2y/7a

Answer 20

Let me think for a moment. >_> Gonna check if my answer are correct.

Answer 21

No problem..

Answer 22

Did the paper say, 5(3ax+y)=8ax -3y for x
something like that?

Answer 23

Yes exactly

Answer 24

Substituting didn't work, I guess that means multiplication. Give me 1m minute.

Answer 25

Okay Thanks.

Answer 26

I think I know the answer. Its written as 5(3ax+y)=8ax -3y for x
Subtract 3y, not comma. >_>

Answer 27

Anyway, distribute.
5(3ax+y)
You know how to do the distributive property?

Answer 28

15ax+5y

Answer 29

Good. Now the equation looks like,
15ax + 5y = 8ax - 3y
Combine like terms.
Do you know how to do that?

Answer 30

Or simplify. >_>

Answer 31

7ax+8y?

Answer 32

Hmm. Well, you know that you can subtract 8ax to both side of the equation to get,
7ax + 5y = -3y

Now you want 5y on the right side of the equation. Do you know how to do that?

Answer 33

Ok, ok. subtract 5y to make -8y?

Answer 34

Yep. 7ax = -8y
Now you want x.
So what do have to do?

Answer 35

Multiply it by 1?

Answer 36

If you do, then the equation would still be the same.
Here's a tip:
7ax can be written as 7 * a * x

So your equation can look like: 7 * a *x = -8 * y

You want x. So you have to do something about 7 * a .

Answer 37

put it under 8y?

Answer 38

Hmm. Put what under 8y?

Answer 39

7a

Answer 40

Great. I think you found your answer.

Answer 41

Thank you so much. Seriously. You dont know how much I appreciate it.
I have to take a College Placement Test and needed help on a few of these, I didn;t understand,

Answer 42

Yeah, no problem. :)