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Factor completely. x3 + 2x2 + x + 2
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First collect like terms x^3+4+x+2 x^3+x+6 Now The factor theorum for polynomials is P(-b/a)=0 when (ax+b) is a factor A general good way to start is by plugging in factors of 6 (1,-1,2,-2....) until you get one to work with. Does this much make sense ?
@Taplin44 your approach is correct but I am afraid that 2x2 stands for 2 times x-square
ahhh that would make so much more sense. i wondered why that would be there, So hard to tell these things apart. nevertheless using the factor theorum and trial and error will get you started, when you find a factor i would use either long or synthetic division to find a quadratic and then factorise that..
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