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Mathematics 14 Online
OpenStudy (anonymous):

State the horizontal asymptote of the rational function. f(x) = x^2 + 8x - 2 / x - 2

OpenStudy (jdoe0001):

\(\bf f(x) = \cfrac{x^2 + 8x - 2 }{ x - 2} \quad ?\)

OpenStudy (jdoe0001):

if that's the case, you really only get a horizontal asymptote when the denominator's "degree" is higher OR equal to the numerator's

OpenStudy (anonymous):

^ yes and these are the answer choices: None y = 1 y = -8 y = 2 @jdoe0001

OpenStudy (jdoe0001):

ok, then you'd know the answer by now then :) what's the degree of the polynomial at the numerator? what about the degree of the one in the denominator?

OpenStudy (anonymous):

2 and then 1

OpenStudy (jdoe0001):

yes, so there

OpenStudy (anonymous):

But those are both different answer choices

OpenStudy (jdoe0001):

----> if that's the case, you really only get a horizontal asymptote when the denominator's "degree" is higher OR equal to the numerator's <----

OpenStudy (anonymous):

so 1 !

OpenStudy (jdoe0001):

1? y = 1?

OpenStudy (anonymous):

2?

OpenStudy (jdoe0001):

hmmmm do you know what -> you really only get a horizontal asymptote when the denominator's "degree" is higher OR equal to the numerator's <- mean?

OpenStudy (jdoe0001):

if the polynomial in the denominator has a higher degree than that of the numerator's, then you have a horizontal asymptote, otherwise, you don't

OpenStudy (anonymous):

Okay so it's none ?

OpenStudy (jdoe0001):

higher or equal btw if the numerator's "degree" is higher than the denominator's, then you have no horizontal asymptotes

OpenStudy (jdoe0001):

so, yes, in this case the degree of the numerator is 2, the denominator is 1 so the numerator's degree is higher, thus no horizontal asymptotes

OpenStudy (anonymous):

Thank youu ((:

OpenStudy (jdoe0001):

yw

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