I NEED TO SLEEP PLEASE ASSIST FOR STUDYING :) How do I simplify radical 5/6
\[\sqrt{\frac{ 5 }{ 6 }}\]
\[\sqrt{\frac{5}{6}}=\frac{\sqrt5}{\sqrt6}\] \[=\frac{\sqrt5}{\sqrt6}\times \frac{\sqrt6}{\sqrt6}\]
when you multiply, the radical in the denominator will be gone, right? because \(\sqrt6\times \sqrt6=6\)
OH yesss
you will be left only with a radical in the numerator, namely \(\sqrt5\times \sqrt6=\sqrt{30}\)
that wasn't too hard was it?
ok well i get how to eliminate the radical from the denominator but that wat do I do with the other half
you are done final answer is \[\frac{\sqrt{30}}{6}\]
you can do no more over out halas get some sleep
I understand now thank you so muchh
I must continue so I will do good on the test tomorrow morning
I need to understand the material
ok you got another one?
Ok well the next one i understand because of how you explained this problem thankfully but i do have another let me write it out
k
\[\left(\begin{matrix}3\sqrt{6} \\ 2\end{matrix}\right)2\] There should be a lne separating two as a denominator but you get it haha
\[\left(\frac{3\sqrt{6}}{2}\right)^2\]?
that is the same as \[\left(\frac{3\sqrt6}{2}\right)\times \left(\frac{3\sqrt6}{2}\right)\] multiply straight across
the denominator is pretty obviously 4 right?
yess
would it be \[\frac{ 18 }{ 2 }\]
how about the numerator? it is \[3\sqrt6\times 3\sqrt6\]
The radical gets eliminated and the product equals whats inside
oops \[3\times 3\times \sqrt6\times \sqrt6=9\times 6=54\]
and \[\frac{54}{4}=\frac{27}{2}\] i think
Yess you're right I think I messed you up the first time!
I forgut to multiply the 3s
i think maybe you forgot to square the 3
Yea exacylu
lol
Thank you so much for all the help I'm finally complete with studying and ACTUALLY UNDERSTAND :))))
yay
Goodnight!
don't make any silly mistakes on the test good luck good night
Thank you I will be sure of that
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