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Mathematics 13 Online
OpenStudy (anonymous):

Expand (2+3x)^3

OpenStudy (anonymous):

just take whats inside the parentheses and cube it right?

OpenStudy (anonymous):

OR do you take (2+3)(2+3)(2+3)

OpenStudy (anonymous):

yah or do the shortcut thing .

OpenStudy (anonymous):

Direct expansion would be faster I think

OpenStudy (anonymous):

so is the answer 8 +27x^3

OpenStudy (anonymous):

Yeah, expand (2+3x)(2+3x)(2+3x)

OpenStudy (anonymous):

wrong Archej1

OpenStudy (austinl):

\((2+3x)(2+3x)(2+3x)=(9x^2+12x+4)(2+3x)=...\)

OpenStudy (anonymous):

He/she forgot the x,x^2 terms

OpenStudy (anonymous):

What austinL said

OpenStudy (austinl):

\((ax^2+bx+c)(d+ex)=(ax^2)(d)+(bx)(d)+(bx)(d)+(ax^2)(ex)+(bx)(ex)+(c)(ex)\)

OpenStudy (austinl):

\(...+(c)(ex)\)

OpenStudy (anonymous):

Here' s the Shortcut . Cube the First term +squared the first term multiply to the second term times 3 + squared the last term multiply to the first term times 3 + cubed the last term .

OpenStudy (anonymous):

it is easy if you know that . :))))

OpenStudy (austinl):

If you do it my way, you are guaranteed a correct answer if you are solid in your algebra skills.

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