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Expand (2+3x)^3
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just take whats inside the parentheses and cube it right?
OR do you take (2+3)(2+3)(2+3)
yah or do the shortcut thing .
Direct expansion would be faster I think
so is the answer 8 +27x^3
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Yeah, expand (2+3x)(2+3x)(2+3x)
wrong Archej1
\((2+3x)(2+3x)(2+3x)=(9x^2+12x+4)(2+3x)=...\)
He/she forgot the x,x^2 terms
What austinL said
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\((ax^2+bx+c)(d+ex)=(ax^2)(d)+(bx)(d)+(bx)(d)+(ax^2)(ex)+(bx)(ex)+(c)(ex)\)
\(...+(c)(ex)\)
Here' s the Shortcut . Cube the First term +squared the first term multiply to the second term times 3 + squared the last term multiply to the first term times 3 + cubed the last term .
it is easy if you know that . :))))
If you do it my way, you are guaranteed a correct answer if you are solid in your algebra skills.
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