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Mathematics 12 Online
OpenStudy (anonymous):

Solve. x2 = 6x – 3

OpenStudy (anonymous):

It looks like a quadratic equation, so move everything to one side using inverse operations and factor.

OpenStudy (anonymous):

you probably want to start with \[x^2-6x=-3\] and then complete the square otherwise start with \[x^2-6x+3=0\] and use the quadratic formula because \(6\) is even, completing the square is probably easiest do you know how to do that?

OpenStudy (anonymous):

Or complete the square.....

OpenStudy (wolf1728):

if you use the quadratic formula then a=1 b= -6 c= 3

OpenStudy (anonymous):

you need to get x by its self so minus it from both sides and you get -4x=-3 and divide both sides to get x by itsself so you answer is x=1

OpenStudy (anonymous):

hope i helped:)

OpenStudy (anonymous):

actually 1 is not the answer

OpenStudy (anonymous):

oh wait yeah sorry i messed up

OpenStudy (anonymous):

if you start with \[x^2-6x=-3\] then take half of 6, which is 3, square it to get 9 and then write \[(x-3)^2=-3+9=6\] take the square root, don't forget the \(\pm\) and get \[x-3=\pm\sqrt6\] then add 3 to both sides and you are done

OpenStudy (anonymous):

I had gotten stuck on this part x^2 - 6x +3 = 0

OpenStudy (wolf1728):

Quadratic formula is: x = [-b +-sqroot(b² - 4*a*c)] / 2a

OpenStudy (anonymous):

I got x = 10.9 or x = -1.1 is it wrong?

OpenStudy (anonymous):

\[x=3\pm\sqrt6\] is the correct answer

OpenStudy (anonymous):

yeah satellite73 is correct I messed up

OpenStudy (anonymous):

@jbarreto17 Do not estimate the square root unless the question specifically asks you to.

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