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OpenStudy (zzr0ck3r):
what is mapsto?
OpenStudy (zzr0ck3r):
\[x\mapsto\frac{1}{\sqrt{3x+13}}\]
OpenStudy (zzr0ck3r):
what is the qestion?
OpenStudy (anonymous):
I'm sorry. I have no idea, I just copy pasted the equation. I have to find the domain of the function {1}{\sqrt{3 x+13}}?
OpenStudy (zzr0ck3r):
ahh
so we cant divide by 0, and we cant take the square root of a negative number
so we have to make sure both of these dont happen
we can do this buy finding out what x's make this a true statement 3x+13>0
do you understand why?
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OpenStudy (anonymous):
why?
OpenStudy (zzr0ck3r):
well if we let a = 3x+13
we have \[\frac{1}{\sqrt{a}}\]now it should be easy to see why we need a to be greater than 0, and why a cant be 0
do you why a>0 is a must?
OpenStudy (anonymous):
yes
OpenStudy (zzr0ck3r):
ok so we said the thing in the square root, which is in the denominator must be greater than 0
so
3x+13 must be > 0
OpenStudy (anonymous):
okay
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OpenStudy (zzr0ck3r):
you will basiccally have 3 problems with domain
1) square root of negative numbers
2) dividing by 0
3) taking log of non positive numbers
OpenStudy (zzr0ck3r):
basically*
OpenStudy (zzr0ck3r):
in this example you had both 1) and 2)
OpenStudy (anonymous):
okay
OpenStudy (zzr0ck3r):
when I find domain, I dont look for things that x CAN be, I look for things x CANT be.
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