4(2)^3 Why is the answer 32. If I follow PEMDAS, I should do the 4(2) first right?
PEMDAS don't consider caculating series if you calcuate by PEMDAS, PEMDAS calculate by (4*2)^3 So for this calculating, you had better buy scientific calculator avavilable parenthesis function
PEMDAS is explained clearly here: http://www.mathsisfun.com/operation-order-pemdas.html
Ok thanks
It says to do the parens first! Ok so 4x2 is 8, 8^3 is 512! Wrong answer!
in your particular case, it would imply you do the braces first to get:\[4(2)^3=4\times2^3\]then the exponents to get:\[4(2)^3=4\times2^3=4\times8\]
what you calculated was:\[(4\times2)^3=(8)^3=8^3\]
Ok I see the () are for the ^3 not for the 4
yes :)
generally if you something like \(x*(...)^n\) it means first calculate what the \(...\) evaluates to inside the braces, then remove the braces and apply the exponent.
and finally multiply by x
Thank you!
yw :)
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