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Mathematics 17 Online
OpenStudy (explainitlikeimfive):

Write a formula for the general term (the nth term) of the geometric sequence.

OpenStudy (explainitlikeimfive):

OpenStudy (anonymous):

how do you get from the first to the second term?

OpenStudy (anonymous):

wow is that ugly! look at those little minus signs i almost missed them

OpenStudy (explainitlikeimfive):

I dont know where to begin.

OpenStudy (anonymous):

what do you multiply \(\frac{1}{2}\) by to get \(-\frac{1}{10}\) ?

OpenStudy (explainitlikeimfive):

-1/5

OpenStudy (anonymous):

yeah... they're not very clear.

OpenStudy (anonymous):

ikr

OpenStudy (anonymous):

yeah you are right, it is \(-\frac{1}{5}\)

OpenStudy (anonymous):

so each term is the previous term times \(-\frac{1}{5}\)

OpenStudy (anonymous):

\(a_n\) is the \(n\)th term the term before that, i.e. the previous term, is \(a_{n-1}\)

OpenStudy (anonymous):

therefore you could say \(a_n=-\frac{1}{5}a_{n-1}\)

OpenStudy (anonymous):

as usual, the answer is C it is always C

OpenStudy (explainitlikeimfive):

Thank you very much.

OpenStudy (anonymous):

yw

OpenStudy (loser66):

to me, it is \[a_n = \frac{1}{2}(-\frac{1}{5})^{n-1}\]

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