What is an equation of the line, in point-slope form, that passes through the given point and has the given slope? point: (8, –8); slope: 3

Question

akashdeepdeb · Answer

Use the point-slope form a  line.
y-y1 = m(x-x1)
You are given
(x1,y1) = (8,-8)
m = 3

And after doing that write it in the form of y=mx+b :D


Understood?  :)

anonymous · Answer

$$ y - y_1 = m \left( x - x_1\right) \text{, with point} \left( x_1 \text{, } y_1 \right)$$

anonymous · Answer

y-y1 = m(x-x1)
Get the numbers in and answer !

anonymous · Answer

Okay yes I get it , it took me a while LOL

anonymous · Answer

and slope m.  that is point-slope form

akashdeepdeb · Answer

:)

anonymous · Answer

:)

anonymous · Answer

My final answer is y+8=3(x-8)

anonymous · Answer

@AkashdeepDeb

akashdeepdeb · Answer

Yes that is right.
But they are asking us for it to be written in the slope-intercept form.
Open the brackets and write it like this.

y=mx+b
 :D

anonymous · Answer

8 = 3x+8 ?

akashdeepdeb · Answer

y+8=3(x-8)
y+8 = 3x - 24
y = 3x - 32  <---- [This is the form in y=mx+b]

Understood? :)

anonymous · Answer

Ah thanks okay yes I get it