Question

Use basic identities to simplify the expression.

sin^2θ + tan^2θ + cos^2θ

sec^2θ
cos^3θ
sin θ
tan^2θ

Answer 1

u know the double angle equations?

Answer 2

wait, did u mean
\[\sin ^{2}\theta + \tan ^{2} \theta + \cos^{3}\theta?\]

Answer 3

yes!

Answer 4

wait no that's wrong

Answer 5

cos 2 thetha sorry, my typo...

Answer 6

oh yeah then that's right again :O
sorry for the confusion!

Answer 7

sin^2u + cos^2u = 1
and
1 + tan^2u = sec^2u

Answer 8

\[using \cos 2x = \cos^{x} - \sin^{x},\]
\[\sin^{2}x = \cos^{2}x - \cos 2x\]

\[\tan ^{2}x = \frac{ \sin^{2}x }{ \cos^{2}x }\]

Answer 9

oooh okay I got tan^2θ the first time I tried it and I wasn't sure if it was right! Thanks!