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Use basic identities to simplify the expression. sin^2θ + tan^2θ + cos^2θ sec^2θ cos^3θ sin θ tan^2θ
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u know the double angle equations?
wait, did u mean \[\sin ^{2}\theta + \tan ^{2} \theta + \cos^{3}\theta?\]
yes!
wait no that's wrong
cos 2 thetha sorry, my typo...
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oh yeah then that's right again :O sorry for the confusion!
sin^2u + cos^2u = 1 and 1 + tan^2u = sec^2u
\[using \cos 2x = \cos^{x} - \sin^{x},\] \[\sin^{2}x = \cos^{2}x - \cos 2x\] \[\tan ^{2}x = \frac{ \sin^{2}x }{ \cos^{2}x }\]
oooh okay I got tan^2θ the first time I tried it and I wasn't sure if it was right! Thanks!
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