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The point (3,6) is on the graph of y=2 f(x+1)-4. Find the original point on the graph of y=f(x). I'm honestly at a lost and have no idea what to do.
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(3,6) satisfies y=2 f(x+1)-4 .So plug it in y=2 f(x+1)-4 .What do you get?
so [y=2(3+1)-4 ]
and y=2(6+1)-4?
Nope
The answer in the book is 4,5
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Put x=3 and y=6 at the same time
then i get 6=4
y=2 f(x+1)-4 6=2(f(3+1)-4 10=2f(4) 5=f(4) How you get 6=4?
Ah, i see, I forgot that the numbers in the brackets manipulated x and the numbers outside the brackets manipulated y. Thank you!
yw :)
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