Question

Can someone double check my answers for me?

Answer 1

\[14x^6y\]
\[divided by 2xy =\]
times \[3x^4y^2 =\]
\[dividedby 3x^2y^5 = \]
times \[-5x^0y^-3\]

Answer 2

So far I've gotten:

14x^6y^(1)/2xy(1) = 7x^5 3x^4y^2)
= 21x^9y^2/3x^2y^-5
= 7x^7y^5/y^2
= 7x^7y^3(-5x^0y^-3) = ?

I'm not sure what that would equal though, wouldn't the ^0 render the whole equation 1?

Answer 3

x^0=1 :)

Answer 4

so its -5(1)y-3

Answer 5

Okay! -5y^-3(7x^7y^3)

Answer 6

the first step