Question

help with linear inequality systems?

Answer 1

is that university math cause i think my brain just died

Answer 2

lol it's precalc @paul1231

Answer 3

so, exercise 2) only has 1 inequality, that means it's only one line

the line to be graphed from the inequality \(\bf y \le x\) would be \(\bf y = x\)

Answer 4

well, 2) actually has 2 inequalities \(\bf x\ge 0\\ y\le x\)

exercise 3) has 4 inequallities \(\bf 0 \le x \le 4 \implies 0 \le x \ and \ x \le 4\\
---------\\
y \le x\\
x+y \ge 4\)

Answer 5

so lemme do the 1st one, 2)
those 2 inequalities will have 2 graphs, x = 0 and y = x

Answer 6

those alone are the 2 lines for 2)
so test for what are would be the SHADED or TRUE part of the graph, we test points NOT in the line

Answer 7

so let's test say ( 1, 2) x = 1, y = 2
\(\bf x \ge 0 \implies 1 \ge 0 \textit{ is 1 bigger than 0? yes thus TRUE}\\
y \le x \implies 2 \le 1 \textit{ is 2 smaller than 1? no, thus FALSE}\)

so that point didn't work, one yielded true the other false, same point values, thus on that area where (1, 2) is at, is not shaded or is false, or "is not part of the solution"