Question

Solve 3n-40=1/2n+35

Answer 1

n=30

Answer 2

\(\frac{a}{b} = \frac{e}{f} \Rightarrow af = eb\)

Answer 3

can u explain how you worked that out please?

Answer 4

Solve for n:
3 n-40 = n/2+35
Put the fractions in n/2+35 over a common denominator.

Answer 5

Solve for n:
3 n-40 = n/2+35
Put the fractions in n/2+35 over a common denominator.
Put each term in n/2+35 over the common denominator 2: n/2+35 = n/2+70/2:
3 n-40 = n/2+70/2
Combine n/2+70/2 into a single fraction.
n/2+70/2 = (n+70)/2:
3 n-40 = (n+70)/2
Move everything to the left hand side.
Subtract (n+70)/2 from both sides of 3 n-40 = (n+70)/2:
-40+3 n-(n+70)/2 = (n+70)/2-(n+70)/2
Look for two terms that sum to zero.
(n+70)/2-(n+70)/2 = 0:
-40+3 n-(n+70)/2 = 0
Put the fractions in -40+3 n-(n+70)/2 over a common denominator.
Put each term in -40+3 n-(n+70)/2 over the common denominator 2: -40+3 n-(n+70)/2 = (-80)/2+(6 n)/2+(-70-n)/2:
(-80)/2+(6 n)/2+(-70-n)/2 = 0
Combine (-80)/2+(6 n)/2+(-70-n)/2 into a single fraction.
(-80)/2+(6 n)/2+(-70-n)/2 = (6 n+(-70-n)-80)/2:
(6 n-n-80-70)/2 = 0
Group like terms in 6 n-n-80-70.
Grouping like terms, 6 n-n-80-70 = (6 n-n)+(-80-70):
((6 n-n)+(-80-70))/2 = 0
Combine like terms in 6 n-n.
6 n-n = 5 n:
(5 n+(-80-70))/2 = 0
Evaluate -80-70.
-80-70 = -150:
(5 n+-150)/2 = 0
Factor the polynomial, 5 n-150.
Factor 5 from the polynomial 5 n-150:
5 (n-30)/2 = 0
Multiply both sides by a constant to simplify the equation.
Multiply both sides of (5 (n-30))/2 = 0 by 2/5:
((2×5 (n-30))/(5))/(2) = 2/5×0
Express 2/5×0 as a single fraction.
2/5×0 = (2×0)/5:
(2×5 (n-30))/(5×2) = (2×0)/5
Cancel common terms in the numerator and denominator of (2×5 (n-30))/(5×2).
(2×5 (n-30))/(5×2) = (5×2)/(5×2)×(n-30) = n-30:
n-30 = (2×0)/5
In (2×0)/5, divide 0 in the numerator by 5 in the denominator.
0/5 = (5×0)/5 = 0:
n-30 = 2×0
Any number times zero is zero.
0×2 = 0:
n-30 = 0
Isolate terms with n to the left hand side.
Add 30 to both sides:
n+(30-30) = 30
Look for two terms that sum to zero.
30-30 = 0:

Answer 6

thank you