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OpenStudy (anonymous):
what do i do to get x = 0 or x = 9 from here x2 + 9x = 0
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OpenStudy (anonymous):
Factor out a common term.
OpenStudy (anonymous):
question
OpenStudy (anonymous):
?
OpenStudy (anonymous):
is it (x - 9)(x + 9)
OpenStudy (anonymous):
No, if you FOIL those terms you will get \(x^2-81\).
There is a single factor that is common to both terms. \(x^2+9x\)
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OpenStudy (anonymous):
i'm confused
OpenStudy (anonymous):
What is \(x \times x\)?
OpenStudy (anonymous):
x^2
OpenStudy (anonymous):
What is \(9 \times x\)?
OpenStudy (anonymous):
so is it (x + 3)(x - 3)
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OpenStudy (anonymous):
Nope. If you FOIL those factors you will get \(x^2-9\). Not quite what you are looking for. You may be over thinking it.
What is \(9\times x\)?
OpenStudy (anonymous):
(x + 3)^2
OpenStudy (anonymous):
You are jumping ahead. Answer my questions and you will see a pattern....
\(x\times x=x^2\)
What is \(9 \times x\)?
OpenStudy (anonymous):
9x
OpenStudy (anonymous):
Great! So...
\(x\times x = x^2\)
\(9 \times x = 9x\)
The factors are on the left and the product is on the right.
What factor does each term have?
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OpenStudy (anonymous):
factor \(\times \) factor = product
OpenStudy (anonymous):
thx
OpenStudy (anonymous):
You're welcome.
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