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Mathematics 16 Online
OpenStudy (anonymous):

Can a single ordered pair be a function?

OpenStudy (anonymous):

i want to say no

OpenStudy (anonymous):

That's what I thought but I wasn't sure because they question is worded as follows: Consider the relation {(3,4)} which consists of a single ordered pair. Any set of one or more ordered pairs is a relation. Thus every function is a relation but not every relation is a function. Is this relation a function? What is its domain?

OpenStudy (anonymous):

@phi

OpenStudy (anonymous):

|dw:1378258877057:dw|

OpenStudy (anonymous):

welll its arguable

OpenStudy (anonymous):

Right but it's not a straight line it is just one ordered pair.

OpenStudy (anonymous):

I can't tell....

OpenStudy (anonymous):

well after googling, i guess you can consider it a function? a constant function f(x) = c with a domain of a single point

OpenStudy (anonymous):

Okay. Thanks. I appreciate your help. :)

OpenStudy (anonymous):

sorry, i tried

OpenStudy (phi):

I never thought about this, but I would say yes The requirement for being a function is to be a "well-behaved" relation Any set of one or more ordered pairs is a relation. So one ordered pair is a relation. A well-behaved relation means given an x, we get only and exactly one y which is true for one ordered pair. So the ordered pair (x0,y0) meets the criteria of being a well-behaved relation, which makes it a function, with domain of one value x0 and a range of one value, y0

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