._. I don't understand how to get the answer. lol
Proglem..
find f of g
f(x)= (3 root) x-1
Uhh the three is front of the root sign and the x-1 is under the root. I'll retype it here one sec...

Oh the answer is apparently x..

Question

._. I don't understand how to get the answer. lol
Proglem..
find f of g 
f(x)= (3 root) x-1
Uhh the three is front of the root sign and the x-1 is under the root. I'll retype it here one sec...

Oh the answer is apparently x..

b2st · Answer

$$\sqrt[3]{x-1}$$

b2st · Answer

^ this what I meant. lol and the answer is apparently x. 
How do you get that?

anonymous · Answer

you could say $g(x)=x-1$ and $f(x)=\sqrt[3]{x}$ which would make 
$$f\circ g(x)=f(x-1)=\sqrt[3]{x-1}$$

b2st · Answer

Thanks! But I'm still confuse. o.o Why did you do that?

anonymous · Answer

because that is what you asked right? write 
$$\sqrt[3]{x-1}$$ as a composite function

b2st · Answer

Yes, I did. 
My math teacher didn't really lecture about this part of solving. O ^ O

anonymous · Answer

what would you do if you had a number for $x$?  like say $x=9$
1) subtract 1  to get $9-1=8$(that is the first function)
2) take the cubed root (that is the second function)