Volume A box 10 inches high has a square base. The box was made 9 inches longer, and 3 inches narrower (or its width was decreased by 3 inches) while the height remained 10 inches. Give the original length of one side of the box if these changes increased the volume of the box by 50
put them into an equation of volumes let the square base be x 10 x^2 = 10(x+9)(x-3) + 50
Original volume = 10 × y × y New volume = 10 × (y+9) × (y-3) New Volume - Original Volume = 50 10(y+9)(y-3) - 10(y)(y) = 50 Solve for y
@DDCamp i believe you got that backwards :P 10yy - 10(y+9)(y-3) = 50 Volume increased after change so ..
@nphuongsun93 Yes, the volume increased, so the new volume must be larger. So the new volume - the old volume would be a positive 50.
"The box was made"
anyway just solve this 10 x^2 = 10(x+9)(x-3) + 50
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