Mathematics
8 Online
OpenStudy (anonymous):
(1/2)x + (1/4)x = 16
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OpenStudy (anonymous):
First do + because we have only x s :
Means :
(1/2+1/4)x
OpenStudy (anonymous):
A.16
B.21.3
C.32
D.64
OpenStudy (anonymous):
these are the choices
OpenStudy (anonymous):
divide each side by 2
OpenStudy (anonymous):
Okay, then what
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OpenStudy (anonymous):
divide each side by 4
OpenStudy (anonymous):
what would the answer be
OpenStudy (anonymous):
u tell me?
OpenStudy (anonymous):
Im working on it
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
This is a little tough, i havent done this in a while
OpenStudy (anonymous):
im sorrry i meant multiply everything on the left side by 2.
OpenStudy (anonymous):
and the right side
OpenStudy (anonymous):
ohhhh, well that makes this easier,
OpenStudy (anonymous):
i got 4/4
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OpenStudy (anonymous):
i dont get it
OpenStudy (anonymous):
no... okay what did you get when you multiplied everything by 2
OpenStudy (anonymous):
hold on, 2/4+ 2/8
OpenStudy (anonymous):
thats what i got
OpenStudy (anonymous):
i said everything by 2/1 or 2
so u should get...
x+ 2/4x=32
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OpenStudy (anonymous):
2(1/2x) + 2(1/4x) = 2(16)
OpenStudy (anonymous):
2/2x + 2/8x = 32
OpenStudy (anonymous):
correct! now do the rest and see what u get.
OpenStudy (anonymous):
4/10x=32
OpenStudy (anonymous):
actually no its 2/2x + 2/4x = 32
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OpenStudy (anonymous):
2/4x not 2/8x
OpenStudy (anonymous):
whats the answer
OpenStudy (anonymous):
u tell me... if you have 2/2x + 1/4 x = 16 do the rest. its pretty simple.
OpenStudy (anonymous):
3/6x=16
OpenStudy (anonymous):
*i mean if you have 2/2x + 2/4 x = 16
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OpenStudy (anonymous):
so 2/2 is also 1... so change 2/2x to 1x or x
OpenStudy (anonymous):
then what
OpenStudy (anonymous):
now you would have x + 2/4x = 32
OpenStudy (anonymous):
WE have :
(1.2+1.4)x=16
2 .6x=16
x= 16/26/10
X = 160/26
OpenStudy (anonymous):
so,which answer is it(answer choices at the top)
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OpenStudy (anonymous):
No one !
I m sure for my answer .
I think you cant say the question well .
Or the question is fall !:
OpenStudy (anonymous):
C