Question

how many solutions does this have?

4m-2n=16 and n=2m-3

Answer 1

notice you can write
n= 2m -3 as
3+n = 2m (add +3 to both sides)
3= 2m - n (add -n to both sides)

multiply both sides by 2
6 = 2(2m-n)
6 = 4m -2n
or

4m - 2n = 6

now compare this to the other equation
4m-2n= 16

Answer 2

ok what am i sopossed to see

Answer 3

the first equation says, there are two numbers m and n, and when you multiply m by 4 and subtract 2 times n you get 6

the second equation says, "do the same thing and you get 16"

in other words, both equations cannot be true at the same time.
a solution to two equations is something that makes both true *at the same time*

Answer 4

so theres only one solution?

Answer 5

Here is another way to do this
4m-2n=16 and n=2m-3

replace n with 2m-3 (because the 2nd equation says n is the same as 2m-3)

4m - 2(2m-3)= 16

distribute the -2: 4m -4m + 6 =16
4m - 4m is 0, so this simplifies to
6 = 16

which is not true. That is a sign there is no solution

Answer 6

o ok this helps a lot thanks for the help