Question

-5y - 9=-(y - 1) solve please real quick need answer :)

Answer 1

Solve for y:
-9-5 y = 1-y
Move terms with y to the left hand side.
Add y to both sides:
-(5 y)+y-9 = (-y+y)+1
Look for two terms that sum to zero.
-y+y = 0:
-(5 y)+y-9 = 1
Move everything to the left hand side.
Subtract 1 from both sides of y-5 y-9 = 1:
-(5 y)+y-9-1 = 1-1
Look for two terms that sum to zero.
1-1 = 0:
-(5 y)+y-9-1 = 0
Add the numbers in -(5 y)+y-9-1 together.
Add like terms. -9-1 = -10:
-5 y+y-10 = 0
Factor the polynomial, -5 y+y-10.
Factor -2 from the polynomial -4 y-10:
-2 (5+2 y) = 0
Divide both sides by a constant to simplify the equation.
Divide both sides of -2 (2 y+5) = 0 by -2:
(-2 (2 y+5))/(-2) = 0/(-2)
Any nonzero number divided by itself is one.
(-2)/(-2) = 1:
2 y+5 = 0/(-2)
Any number times zero is zero.
0/(-2) = 0:
2 y+5 = 0
Isolate terms with y to the left hand side.
Subtract 5 from both sides:
2 y+(5-5) = -5
Look for two terms that sum to zero.
5-5 = 0:
2 y = -5
Solve for y.
Divide both sides of 2 y = -5 by 2:
(2 y)/(2) = -5/2
Any nonzero number divided by itself is one.
2/2 = 1:
Answer: |
| y = -5/2

Answer 2

thank you so much!

Answer 3

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