HELP!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!! The equation of a circle is shown below. (x -5)2 + (y + 2)2 = 64 The radius of the circle is ________ units. (No Multiple Choice)
@.Sam. @andriod09 @Gin_Ichimaru @ganeshie8 @Hunter15 @Creation @aaronq @lalokio
@hba @Frostbite @Hero @lexi14 @phi @Meriam
But what's the answer!?
I'm confused!!!!!!!!!!!!
\[(x-h)^2+(y-k)^2=r^2\] is the equation of a circle with radius \(r\) and center \((h,k)\)
in your case \(r^2=64\) what is \(r\) ?
And how do I translate that into the real equation?
I actuall don't know what R is. :/
\[(x-h)^2+(y-k)^2=r^2\\(x-5)^2+(y+2)^2=64\] look almost identical
okay, so it's 64. Right?
\(r^2\) is 64 but you are asked for the radius, which is \(r\) what number would you square to get 64?
8?
yes
so that's the answer, right? 8?
hello? :(
yes
okay, thanks. :)
\(64=8^2\) so \(r=8\) yw
thanks. :)
Wait guys, I have another question. segment PR has an endpoint at (25, -5) and a midpoint of (18, -1). What is the value of the x-coordinate of the other endpoint?
@satellite73 @Loser66 @geoffb
(this one is also not multiple choice.)
post at a new post, friend
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