Question

find the verticle asymptote of f(x)= 1/(x^2 -4)
and describe the behavior of f(x) to the left and right of each asymptote? help PLEASE?D: (:

Answer 1

2 Vertical asymptotes. 1 at x=2, and the other at x=-2. Because (x^2-4) --> (x-2)(x+2)

Answer 2

or you could also say that they are going towards 0 because they never cross the x-axis

Answer 3

is this the correct graph?

Answer 4

@SoccerGirl13, just out of curiousity, what kind of calculator do you have?

Answer 5

ti-84 :o

Answer 6

I see

Answer 7

Do you know how to program the function into your calculator?

Answer 8

If you did, that would help you out a lot

Answer 9

yes, but what i'm having trouble with is identifying the limits. :(

Answer 10

wait what do you mean by program the function into it?

Answer 11

If you don't know how to, then nevermind.

Answer 12

Explaining how to program a calculator from OS would be a project.

Answer 13

They question asked to explain the behavior of f(x) to the right and left of each asymptote.

Answer 14

yess, that was the second part of the question! :o

Answer 15

If you've already graphed the function, then I assume that you have already found the vertical asymptotes. And from the graph, you should be able to describe its behavior.

Answer 16

would you say that both sides are going towards zero, or that the left side is going towards negative infinity and right towards infinity? :o .__.

Answer 17

@Hero ? any clue? O; :(

Answer 18

In this case, one side is approaching infinity and the other is approaching y = 0