Question

Choose the correct graph of the following system of inequalities:

4x – 3y < –12
x – 6y greater than or equal to 6

Answer 1

@nirmalnema can u help?

Answer 2

u have any idea which one is correct...

Answer 3

no

Answer 4

u know how to solve it

Answer 5

no

Answer 6

first replace the equality sign

Answer 7

and solve the equality..
and get the intersection point

Answer 8

you should learn how to change the equations
4x – 3y < –12
into slope-intercept form so you can find the lines.

but you can do this: test the point (0,0)
in both relations. that means replace x and y with 0
4x – 3y < –12
x – 6y >= 6

you will get 0 < -12 ? and 0 ≥ 6 ?
both are false. So you should ignore any graph that has (0,0) colored in.

Answer 9

Can you see what choices the answer might be ?

Answer 10

hold on

Answer 11

i eliminated b an d

Answer 12

i think its either a or c?

Answer 13

yes. Now which one, a or c ?

there is only one difference between the two graphs. They switched which line has a solid line (meaning ≤) and a dotted line (meaning <)

you have to figure out which line should be solid and which is dotted.
x – 6y >= 6 will be the solid line (because of = part of >=)

one of the lines goes through (0,-1) (can you see that)
which of the lines

4x – 3y < –12
x – 6y >= 6

goes through (0,-1). to find out , replace x with 0 and y with -1
which one has the point (0,-1) *on the line*

can you figure that out ?

Answer 14

is it c?

Answer 15

Here is what you get if you put (0,-1) into both equations
4x – 3y < –12 ---> -3*-1 = -12 ? 3 = -12 NO
x – 6y >= 6 ----> -6*-1 = 6 ? 6 = 6 YES

what that means is the line going through (0,-1) is x-6y≥6 (and should be solid)

Answer 16

so is it c?

Answer 17

@phi

Answer 18

the site went flakey!

the line going through (0,-1) is x-6y≥6 (and should be solid)

I would pick the graph that is a solid line going through the point x=0, y = -1