Question

for the love of god ive been up all night someone please just tell me the answers to each of these

-2<2x-4<4

2|3x-5|-8=8

6|6-4x|=8x +4

8|x+ 30ver4|<2

Answer 1

the last one is supposed to say 3 over 4

Answer 2

\[6\left| 6-4x \right|=8x+4\]
\[\left| 6-4x \right|=\frac{ 8x+4 }{ 6 }\]
\[6-4x=\pm \frac{ 8x+4 }{ 6 }\]

Answer 3

whats the answer haha

Answer 4

\[either 6-4x=\frac{ 8x+4 }{6 }\]
6(6-4x)=8x+4
36-24x=8x+4
36-4=8x+24x
32x=32,x=32/32=1

Answer 5

ok that was correct what are the other answers

Answer 6

\[or6-4x=-\frac{ 8x+4 }{6 }\]
6(6-4x)=-(8x+4)
36-24x+8x+4=0
36+4=24x-8x
16x=40
x=40/16=5/2

Answer 7

answer my other questions not just that one

Answer 8

i solved a bit difficult ,others ar easy. you start i will guide you.

Answer 9

omg

Answer 10

let us start with first.
write the statement first.

Answer 11

then add 4 in all the three inequalities.

Answer 12

6?

Answer 13

not like this
-2+4<2x-4+4<4+4
2<2x<8
now divide each inequality by 2

Answer 14

1<x<4

Answer 15

how you got 6 ?

Answer 16

now write the second statement and show me.

Answer 17

\[2\left| 3x-5 \right|-8=8\]
\[2\left| 3x-5 \right|=8+8\]
\[\left| 3x-5 \right|=\frac{ 16 }{2 }=8\]
\[3x-5=\pm8\]

Answer 18

either 3x-5=8 or 3x-5=-8
now you can solve these equations for x.

Answer 19

are you solving ?

Answer 20

\[8\left| x+\frac{ 3 }{4 } \right|<2\]
\[\left| x+\frac{ 3 }{4 } \right|<\frac{ 2 }{8}\]
\[\left| x+\frac{ 3 }{ 4 } \right|<\frac{ 1 }{4 }\]
\[-\frac{ 1 }{ 4 }<x+\frac{ 3 }{4 }<\frac{ 1 }{4 }\]
multiply by 4
-1<4x+3<1
subtract 3
-1-3<4x+3-3<1-3
-4<4x<-2
divide by 4
\[-1 <x<\frac{ -2 }{ 4 },or-1<x<-\frac{ 1 }{2 }\]