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Evaluate the limit of x/(absolute value of x) as x approaches 0- (from the left side). ???
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\[\Large \left(|x|\right)' \quad=\quad \frac{x}{|x|}\]
\[ f(x) = \frac x {|x|} \]
Since \(x\leq 0\) we know \(|x| = -x\)\[ \frac x{|x|}\to \frac x{-x} \to -1 \]
But if x\[\le0\], shouldn't that -x be \[\left| -x \right|\]?
Suppose \(x=-1<0\) Then \(|x|=|-1| = 1 = -x\)
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I see what you're saying now.
The thing is that \(-x\) doesn't make \(x\) negative. It changes the sign of \(x\). Negative \(x\) values need to change sign to become positive.
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