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Find two real numbers b such that the algebraic expression is a perfect square trinomial. 16x^2 + bxy +25y^2
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@saifoo.khan please explain your answer
Do you know how to do the completing square?
I now believe its 20 and -20. I tried working it out again : 16x^2 + bxy + 25y^2 \[(16x ^{2} + 20xy) + (20xy +25y ^{2})\] I got 20xy from doing a*c, 16 * 25. Which equals 40. And then i to the square root of that to get 20.
This then factors down to \[(4x+5y)^{2}\] which is a perfect square
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You're right!
So b is going to be 40.
Oh yes thats right! Almost overlooked that
you know it can b -40 too, right ?
thts why they asked in the question, "two" values
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