Question

Write the equation of the quadratic function with roots -9 and and -3 and a vertex at (-6, -1). Answer

Answer 1

please help

Answer 2

you can always write parabola as \[y=a \left( x-x _{1} \right)\left( x-x _{2} \right)\] where x1 and x2 are roots of parabola and a is just constant

Answer 3

so it would be y=a(x+9)(x+3)

Answer 4

yes thats right and now substitute vortex point in the ecuation and you will get a

Answer 5

-6(x+9)(x+3)
like tht?

Answer 6

did you substitute -6 for x and -1 for y? because i got different a

Answer 7

idk how to do this

Answer 8

i got f(x)=x^2-12x+27

Answer 9

a(-6+9)(-6+3)=-1

Answer 10

a(3*-3)=-1
a(-9)=-1

Answer 11

a=8

Answer 12

?

Answer 13

why are you adding 9 when you should divide by 9

Answer 14

so its 1/9

Answer 15

yes

Answer 16

thanks now wat do i do if i want the full equation

Answer 17

multiply out (1/9)(x+9)(x+6)

Answer 18

ok just a moment

Answer 19

not x+6 a should write x+3

Answer 20

sorry :)

Answer 21

ok i got

Answer 22

x^2/9+4x+3+3

Answer 23

i wrote wrong equation up (1/9)(x+3)(x+9) :D sorry about that

Answer 24

ok

Answer 25

im so confused
can you tell me the equation you got

Answer 26

what confusis you? y=a(x-x1)(x-x2) you know a x1 and x2 put them in you will get y=(1/9)(x+3)(x+9) now multiply it out and you will get answer

Answer 27

y=1/9x^2-1.3x+3

Answer 28

4/3 is not 1.3

Answer 29

i think you have some problems in arithamtics

Answer 30

ok first just multipla
(x+9)(x+3)=x^2+3x+9x+27=x^2+12x+3

Answer 31

This is wrong because i put this in a calculator that determines the equations for quadratic functions and it said that this equation is with the toots of 9,3 and the vertex is -6,1

Answer 32

which equation y=(1/9)(x+9)(x+3) is wright

Answer 33

you just multiplied it out wrongly

Answer 34

you must get x^2/9+4x/3+3

Answer 35

oh thank u so much got the answer i appreciate your patience

Answer 36

it was my foult i'm not great at explaning :)