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Algebra 7 Online
OpenStudy (anonymous):

Help?

OpenStudy (anonymous):

ganeshie8 (ganeshie8):

average rate of change = change in y / change in x

ganeshie8 (ganeshie8):

you're going from x=3 to x=5 so, chang ein x = 5-3 = 2

ganeshie8 (ganeshie8):

do u knw how to find change in y, from the given table ?

OpenStudy (anonymous):

But what about the 1 ?

OpenStudy (anonymous):

And no , all of this is confusing to me :(

ganeshie8 (ganeshie8):

its okay to get confuse when u start... did u get how we got the change in x ?

OpenStudy (anonymous):

Yes, we subtracted them? :o

ganeshie8 (ganeshie8):

yes, now look at table. and tell me wats the y value, when x = 5 and when x = 3

OpenStudy (anonymous):

When x=5 , the y value is -2 . When x=3 , the y value is 4

ganeshie8 (ganeshie8):

excellent ! so change in y = -2-4 = -6

ganeshie8 (ganeshie8):

average rate of change = change in y / change in x = -6/2 = -3

ganeshie8 (ganeshie8):

see if that makes sense

OpenStudy (anonymous):

That does makes sense ! :D

ganeshie8 (ganeshie8):

cool :)

OpenStudy (anonymous):

Thank you so much, I have a few more questions? Would you be willing to help?

ganeshie8 (ganeshie8):

sure ask :)

OpenStudy (anonymous):

I will attach it as a picture so it will be easier :)

ganeshie8 (ganeshie8):

find m, the rate of change of first

ganeshie8 (ganeshie8):

(-1, 3) and (1 , 7)

ganeshie8 (ganeshie8):

those are the given points

ganeshie8 (ganeshie8):

(-1, 3) and (1 , 7) x1 y1 x2 y2

ganeshie8 (ganeshie8):

rate of change , m = change in y / change in x = y2-y1 / x2-x1

ganeshie8 (ganeshie8):

= 7-3 / 1--1 = 4/2 =2 so, m = 2

OpenStudy (anonymous):

Right :) I'm working it out on paper with you :P

ganeshie8 (ganeshie8):

now, use this :- equation of line in slope, point form is, y - y1 = m(x-x1) plugin values :)

OpenStudy (anonymous):

That would be y - 3 = 2 (x - (-1)) ?

ganeshie8 (ganeshie8):

Yes !

OpenStudy (anonymous):

Yay !!

OpenStudy (anonymous):

So is that it ? :o

ganeshie8 (ganeshie8):

not yet, thats one equation. we could have used the second point aswell... let me do it for you :)

OpenStudy (anonymous):

Oh , okay :) Thank you !

ganeshie8 (ganeshie8):

slope m = 2, second point (1 , 7) so m = 2, x1 = 1, y1=7 y-y1 = m(x-x1) plugin values now

ganeshie8 (ganeshie8):

y-7 = 2(x-1)

ganeshie8 (ganeshie8):

thats the second equation. now see which one exists in the given options , and tick that one...

OpenStudy (anonymous):

It's option 2 ! :)

OpenStudy (anonymous):

You helped me understand this ! Thank you :D

ganeshie8 (ganeshie8):

Yes ! takes time to master these... i see you're already getting good at these :)

OpenStudy (anonymous):

I have 3 more questions left and 2 are easy , once I answer those may you help me with the very last question ?? Pleasee :p

ganeshie8 (ganeshie8):

np, i hav time :)

ganeshie8 (ganeshie8):

just holler when u r done wid the two prblms... ;)

OpenStudy (anonymous):

Haha okay !! :)

OpenStudy (anonymous):

Okay here's the last question :) Jack and Jill had 3 pails of water. Each trip up the hill, Jack and Jill obtained 1 more bucket of water. Which of the graphs below represents Jack and Jill's number of pails over time?

ganeshie8 (ganeshie8):

check ur 3rd & 4th graphs. they are same !

OpenStudy (anonymous):

That's how it is on my quiz :( It's probably an error ... Is there anyway to do this and figure out the answer and see if it's on one of the graphs ? If not , I don't think my teacher will deduct points for the question being incorrect lol

ganeshie8 (ganeshie8):

ohk, but wat wud u pick whe u have two exact same graphs ?

OpenStudy (anonymous):

Ugh I'm just going to chose an answer and tell my teacher there was an error with the questions . Thank you though :)

ganeshie8 (ganeshie8):

good :) here is how we solve it :- since to start with, they have 3 pails of water, that means, the line must cit the y- axis at 3

ganeshie8 (ganeshie8):

since the line is cutting y-axis at 3 only in 3rd & 4th graphs, one of them must be ur answer

ganeshie8 (ganeshie8):

and since, both graphs are exact same, u toss a coin and pick one

OpenStudy (anonymous):

Haha okay :) Thank you so much for your help :)

ganeshie8 (ganeshie8):

np :) goodluck wid ur assignment :)

OpenStudy (anonymous):

WAITTT ! This one ?? :o

OpenStudy (anonymous):

Can you help ? :o

ganeshie8 (ganeshie8):

ha, take first equation, and solve x

ganeshie8 (ganeshie8):

first equaiton :- 2x+4 = 3x-11

ganeshie8 (ganeshie8):

can you solve x ?

OpenStudy (anonymous):

Yes, give me a minute :)

ganeshie8 (ganeshie8):

take ur time =)

OpenStudy (anonymous):

The answer is 3 :)

OpenStudy (anonymous):

Second one is 16

OpenStudy (anonymous):

I need help solving the last one ...

ganeshie8 (ganeshie8):

second one is 16 \(\checkmark \)

ganeshie8 (ganeshie8):

but first one is not 3

OpenStudy (anonymous):

It's not ? :( What's the first one ?

ganeshie8 (ganeshie8):

2x+4 = 3x-11 subtract 2x both sides 4 = x - 11 add 11 both sides 15 = x

ganeshie8 (ganeshie8):

first one is 15

OpenStudy (anonymous):

Ohhhhh ! I know what I did wrong ! I added 3x and 2x by mistake ! haha

ganeshie8 (ganeshie8):

:) i thought so... third equation :- \(\large \frac{2x+1}{3} = \frac{x+6}{2}\)

ganeshie8 (ganeshie8):

cross multiply

OpenStudy (anonymous):

How would I start ? :( I'm no good in cross multiplying ..

ganeshie8 (ganeshie8):

\(\large \frac{2x+1}{3} = \frac{x+6}{2}\) \(\large 2(2x+1) = 3(x+6)\)

OpenStudy (anonymous):

Omg that makes sense -.- ! Okay I understand now !

ganeshie8 (ganeshie8):

cool :) solve x

ganeshie8 (ganeshie8):

\(\large \frac{2x+1}{3} = \frac{x+6}{2}\) \(\large 2(2x+1) = 3(x+6)\) \(\large 4x+2 = 3x+18\) solve x

OpenStudy (anonymous):

4x + 2 = 3x + 18 ? Then solve ?

ganeshie8 (ganeshie8):

yes !

OpenStudy (anonymous):

Okay one moment !

ganeshie8 (ganeshie8):

oki

OpenStudy (anonymous):

Is x = -16 ?

ganeshie8 (ganeshie8):

\(\large \frac{2x+1}{3} = \frac{x+6}{2}\) \(\large 2(2x+1) = 3(x+6)\) \(\large 4x+2 = 3x+18\) subtract 3x both sides \(\large x+2 = 18\)

ganeshie8 (ganeshie8):

that gives, x = ?

OpenStudy (anonymous):

Oh sorry I subtracted 4x by mistake !

ganeshie8 (ganeshie8):

ok.. x = ?

OpenStudy (anonymous):

One sec

ganeshie8 (ganeshie8):

\(\large \frac{2x+1}{3} = \frac{x+6}{2}\) \(\large 2(2x+1) = 3(x+6)\) \(\large 4x+2 = 3x+18\) subtract 3x both sides \(\large x+2 = 18\) subtract 2 both sides \(\large x = 16\)

OpenStudy (anonymous):

Should be 16 !

ganeshie8 (ganeshie8):

x = 16 ! :)

OpenStudy (anonymous):

Yay :D

OpenStudy (anonymous):

So equations 1 and 3 have the same solution !

ganeshie8 (ganeshie8):

yes ! so we got, first one, x = 15 second one, x = 16 third one, x = 16

ganeshie8 (ganeshie8):

careful madam, equations 2 and 3 have the same solution

OpenStudy (anonymous):

THANK YOU THANK YOU THANK YOU !! :) & yes I got confused haha but now i get it :)

ganeshie8 (ganeshie8):

glad to hear that :) you're wlcme !!

OpenStudy (anonymous):

Are you willing to help me out with 4 more questions ? And that it for the day !! Haha

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