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Mathematics 17 Online
OpenStudy (anonymous):

Statisticssssss -_______- Assume that there is a %8 rate of disk drive failure in a year. a. If all your computer data is stored on a hard disk drive with a copy stored on a second hard disk drive, what is the probability that during a year, you can avoid catastrophe with at least one working drive? b. If copies of all your computer data are stored on three independent hard disk drives, what is the probability that during a year, you can avoid catastrophe with at least one working drive? Round to four decimal places.

OpenStudy (anonymous):

This is a binomial distribution.

OpenStudy (anonymous):

\[ X\sim B(n,p) \implies \Pr(X=k) = \binom nk p^{k}(1-p)^{n-k} \]

OpenStudy (anonymous):

Yeah, I can.

OpenStudy (anonymous):

Do you know what \(\binom n k\) is?

OpenStudy (anonymous):

n choose k

OpenStudy (anonymous):

Ok. So if you have two drives, how many ways are there for one to remain?

OpenStudy (anonymous):

Yes

OpenStudy (anonymous):

What is the probability for 1 to remain?

OpenStudy (anonymous):

Not quite.

OpenStudy (anonymous):

Okay suppose we give them a letter. There is dive A and drive B.

OpenStudy (anonymous):

What is the probability that drive A fails and the probability that drive B doesn't fail?

OpenStudy (anonymous):

"Assume that there is a %8 rate of disk drive failure in a year."

OpenStudy (anonymous):

What is the probability that drive A fails?

OpenStudy (anonymous):

That is the simplest I can get it.

OpenStudy (anonymous):

92% is that it doesn't fail.

OpenStudy (anonymous):

Now, does the failure of drive A affect the failure of drive B? Is it independent?

OpenStudy (anonymous):

Well it is independent.

OpenStudy (anonymous):

They are independent because they don't affect each other. Drive A will fail or not fail with the same probability regardless of whether drive B fails.

OpenStudy (anonymous):

What is the probability of two independent events happening? Do you remember any formula?

OpenStudy (anonymous):

This isn't conditional probability.

OpenStudy (anonymous):

What is the probability of BOTH independent events happening.

OpenStudy (anonymous):

\[ \Pr(AB) = \Pr(A) \times \Pr(B) \]

OpenStudy (anonymous):

When \(A,B\) are independent.

OpenStudy (anonymous):

IN this case \(\Pr(A)= 0.08\) and \(\Pr(B) = 0.92 = 1-0.08\)

OpenStudy (anonymous):

And \(A\) is the event drive \(A\) fails and \(B\) is the event \(B\) doesn't fail.

OpenStudy (anonymous):

We have 0.0736 that A fails and B doesn't fail.

OpenStudy (anonymous):

Next we need the probability that A doesn't fail and B fails.

OpenStudy (anonymous):

Let's keep it simple for now.

OpenStudy (anonymous):

Okay

OpenStudy (anonymous):

What is the probability that A doesn't fail and B fails?

OpenStudy (anonymous):

probability that A doesn't fail is .92

OpenStudy (anonymous):

probability that B does is .08

OpenStudy (anonymous):

yeah but for both?

OpenStudy (anonymous):

IT's the same as before

OpenStudy (anonymous):

Yes.

OpenStudy (anonymous):

Now one last one we need to do. What is the probability that A doesn't fail and B doesn't fail.

OpenStudy (anonymous):

Okay

OpenStudy (anonymous):

So we have probabilities for: A fails, B doesn't A doesn't, B fails A doesn't, B doesn't

OpenStudy (anonymous):

There are the 3 ways in which at least one drive doesn't fail.

OpenStudy (anonymous):

They are mutually exclusive events, so the probability of either of them happening is just the sum of them all

OpenStudy (anonymous):

So if we add up all of the probabilities we have calculated we will have the probability that at least one doesn't fail.

OpenStudy (anonymous):

That is the answer to a)

OpenStudy (anonymous):

No. 0.0736 was just the probability that A fails and B doesn't

OpenStudy (anonymous):

The only way to do it faster is to understand it.

OpenStudy (anonymous):

There isn't one simple formula for every problem.

OpenStudy (anonymous):

Where would you start?

OpenStudy (anonymous):

There are a couple formula you should know by now about probability.

OpenStudy (anonymous):

Okay good luck.

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