Precalculus
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OpenStudy (anonymous):
Factor expression: 2X^(3/2)+6X^(1/2)-4X^(-1/2)
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OpenStudy (anonymous):
\[2x ^{\frac{ 3 }{ 2 }} + 6x ^{\frac{ 1 }{ 2 }} - 4x ^{\frac{ -1 }{ 2 }}\]
OpenStudy (anonymous):
?
OpenStudy (anonymous):
yes!
OpenStudy (anonymous):
2x3=6
2x2=4
2x1=2
ok?
OpenStudy (anonymous):
yup
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OpenStudy (anonymous):
so the factor is:
\[2x ^{\frac{ 1 }{ 2 }}(1+3-2^{-1})\]
OpenStudy (anonymous):
wait , in the bracket, isn't it (x+3-....)
OpenStudy (anonymous):
because we factor out x^1/2 from X^3/2
OpenStudy (anonymous):
wait I think I made mistake...
OpenStudy (anonymous):
It will be:
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OpenStudy (anonymous):
\[2x ^{\frac{ 1 }{ 2 }}(x ^{3}+3-2^{-1})\]
OpenStudy (anonymous):
ok?got it?
OpenStudy (anonymous):
why is it X^3?
OpenStudy (anonymous):
3/2 - 1/2 = 1
OpenStudy (anonymous):
shouldn't it be just x
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OpenStudy (anonymous):
x^1 = x
OpenStudy (anonymous):
you are quite right sorry,sorry,sorry...so please write it.
OpenStudy (anonymous):
but i dont know about the last one ...
OpenStudy (anonymous):
1+1/2 = 3/2
OpenStudy (anonymous):
4x^(-1/2) factor out 2x^1/2, leaves what?
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OpenStudy (anonymous):
you are right ;)
OpenStudy (anonymous):
leaves 2^-1?
OpenStudy (anonymous):
wait 'm confused :D let me doing it...
OpenStudy (anonymous):
or 2X^-1
OpenStudy (anonymous):
its ok
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OpenStudy (anonymous):
ok i think it's like......\[2x ^{1/2} (x+3-\frac{ 2 }{ x })\]
OpenStudy (anonymous):
because 2/x = \[2X ^{-1}\]
OpenStudy (anonymous):
well i'm guessing......
OpenStudy (anonymous):
true :)
OpenStudy (anonymous):
ok cool