Prove that (A × B)^2 + (A · B)^2 = A^2B^2

A and B are vectors. (Don't know how to notate them)

Question

Prove that (A × B)^2 + (A · B)^2 = A^2B^2

A and B are vectors. (Don't know how to notate them)

anonymous · Answer

Oh OK !
Wait ...

wolfe8 · Answer

So is it then somehow, (A × B)^2 is = 0?

anonymous · Answer

yes I can be :) just when you put A=0 or B=o it will be :)

anonymous · Answer

sorry it can be not I can be XD

anonymous · Answer

@E.ali , just please show him steps,and don't give the answer at once :)

anonymous · Answer

OK !
@wolfe8
We have :
(A.B)^2=(A.B).(A.B)

wolfe8 · Answer

Well I can technically show it with examples step-by-step, but the question is only worth 3 points. So I'm thinking I must be missing some key identity or something. And I'd really like to know which one.

anonymous · Answer

so you want examples?

wolfe8 · Answer

Not really. Can you tell me if I just need to substitute in some properties in? Is that what I'm missing?

anonymous · Answer

I think you don't need "substitute" at all!

wolfe8 · Answer

I mean 'apply' then

anonymous · Answer

Do u want start ?????!!!!!

anonymous · Answer

maybe I can't understand you :D I can't understand that what exactly do you want!

anonymous · Answer

the proof?

wolfe8 · Answer

Ah sorry. Well yes I need the proof.

wolfe8 · Answer

I'll be in the Mathematics chat

anonymous · Answer

No problem I think:)

wolfe8 · Answer

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