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Mathematics 15 Online
OpenStudy (anonymous):

So I was doing my homework and this is the chain of question I have. "Use the point-slope form linear equation to complete problems 5-18" I got 5-10 need help with the rest y+4=-4(x-2) 5. What is the slope of the given line? 4 6. What point does this line pass through, which is the basis of this equation? (-4,8) 7. Rewrite this equation in slope-intercept form. y= -4x+8 8. What is the y-intercept of this line? 8 9. Rewrite this equation in standard for(not sure if correct). y+4=-4(x-2) 10. What is the x-intercept of this line? -4 11. What is the equation in standard for of a perpendicular line that passes through(5,1)? 12. What is the x-intercept of the perpendicular line? 13. What is the equation in standard form of a parallel line that passes through (0,-2)? 14. On the parallel line, find the ordered pair where x=-2

OpenStudy (anonymous):

You need to back up. Why do you say the slope is 1?

OpenStudy (anonymous):

I though I said 4. Sorry pressed the wrong key on the num lock

OpenStudy (anonymous):

Okay, but do you notice the minus sign?

OpenStudy (anonymous):

yeah, but if you solve it down you can make it into a positive, therefor I got it to a positive, should I keep it at negative?

OpenStudy (anonymous):

It has to be negative. There's a big difference between slope of 4 (steep up slope) and slope of -4 (steep down slope). Now look again at your answer to 6 and see if that's what you really mean.

OpenStudy (anonymous):

Okay. I will correct the rest of the answers! Thanks, can you help with the rest tough?

OpenStudy (anonymous):

I think I have corrected it. Not sure if right tough.

OpenStudy (anonymous):

The main thing you need for the rest is to remember that a perpendicular line has a slope that's the negative reciprocal of the line it's perpendicular to. So if one line has slope -4, a perpendicular line has slope 1/4.

OpenStudy (anonymous):

So -1?

OpenStudy (anonymous):

You can get this but you have to take it step by step. Here's the point-slope form:\[y-y_0=m(x-x_0)\]In this equation, m is the slope, x_0 is the x-coordinate of a known point, and y_0 is the y-coordinate of that point. In the equation you're given, the number that corresponds to m is -4. The number that corresponds to y_0 is also -4, so you have that right. But you don't have the correct number for x_0.

OpenStudy (anonymous):

You need to redo number 7 also. I hope you don't feel I'm picking on you! The equation in number 7 has to have a term that includes x.

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