Question

8xy2 - 14y -----> 2y

Divide

Answer 1

You mean this?

\( 8xy^2 - 14y \div 2y = \dfrac{8xy^2 - 14y}{2y} =\)

Answer 2

mhmm

Answer 3

I am just asking if this is the problem?

\( \dfrac{8xy^2 - 14y}{2y} = \)

Answer 4

If so, then you need to divide each term of the numerator by the denominator:

\( \dfrac{8xy^2 - 14y}{2y} \)

\( = \dfrac{8xy^2 }{2y} - \dfrac{ 14y}{2y} = \)

\( = \dfrac{2 \times 4xyy }{2y} - \dfrac{ 2 \times 7y}{2y} \)

\( = \dfrac{\color{red}{\cancel{2}} \times 4x\color{green}{\cancel{y}}y }{\color{red}{\cancel{2}} \color{green}{\cancel{y}}} - \dfrac{ \color{blue}{\cancel 2} \times 7 \color{orange}{\cancel y}}{\color{blue}{\cancel{2}} \color{orange}{\cancel{y}} }\)

\(=4xy - 7 \)