Eliminate the parameter. x = t2 + 2, y = t2 - 4
to eliminate find t^2 from one equation and substitute in other.
May you guide me, I just got into this chapter and I really do not get it; please.
y=t^2-4 take -4 to other side of equality
CAN YOU WRITE IT ?
y=t^2-4, y=t^2+4?
t^2=y+4 now plug in other equation.
t^2-2
x=t^2+2 x=y+4+2 orx=?
Shouldn't t^2 + 2 be t^2 - 2? y=2/4 + 2. I really don't know.
y=2/4+2 is the answer I think it is.
x =y+6 is the solution.
With your answer I keep getting this question incorrect, so I'll just give you my options; y = x - 6, x ≥ 1 y = x + 6, x ≥ 1 y = x2 - 6, x ≥ 1 y = x2 + 6, x ≥ 1
x=y+6 rearrange it y=x-6
So, is this the correct one: y = x - 6, x ≥ 1?
x should be >=2 but i don't see in your options. otherwise it is correct.
It's correct. Thank You !
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