Question

Help pleaseeeee!(:

The position of an object as a function of time is given by x = At2 – Bt + C, where A = 8.7 m/s2, B = 5.5 m/s, and C = 4.3 m. Find the instantaneous velocity and acceleration as functions of time. (Use the following as necessary: t.)

V=_______
a=_______

Answer 1

V=dx/dt

V=2At-B

a=dv/dt you can find a.

Answer 2

how do i find dv and dt?

Answer 3

dv/dt refers to derivative of v to t. So a=2A

Answer 4

so a would be a=2(8.7)m/s^2 ?
a=17.4 m/s^2?

Answer 5

@Loser66

Answer 6

\[v = \frac{dx}{dt}\] and \[a = \frac{d^2x}{dt^2}\] that's it.

Answer 7

for v, take the first derivative of x , then, plug the value of letter in.
for a, take second derivative of x, then ,plug the value of letter in. Done.

Answer 8

got me?

Answer 9

so far yes. but how do i obtain the values of dx,dt, d^2x and dt^2? @Loser66

Answer 10

don't you know how to take derivative?

Answer 11

what am i taking the derivative of? x=At^2-Bt+C?

Answer 12

yes, it is.

Answer 13

you see, x =.... is a function of t or you can write it as x(t)

Answer 14

x(t)=At^2-Bt+C ? Sorry I'm a bit confused

Answer 15

which grade are you? college? highschool?

Answer 16

college, and I'm struggling badly /; with this and another problem

Answer 17

how about calculus?

Answer 18

I have to know where are you to give out the appropriate instruction.

Answer 19

I took calculus, just trying to recall thing from it..

Answer 20

ok, (t^3)' =?

Answer 21

3t^2?

Answer 22

yes, so, (At^2)' =?

Answer 23

2At?

Answer 24

hahaha.. dan, guide him, please, don't just give out the answer

Answer 25

v=d/dt(f(t))

Answer 26

i'm a her.

Answer 27

do you know v=d/t formula

Answer 28

speed my definition is distance travelled per unit time

Answer 29

velocity= distance/time

Answer 30

velocity=displacement/time but okay

Answer 31

lets move on!

Answer 32

now you have a function here f(t)=x