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Simplify the complex fractions by any method 4y+1/9y^4/y+2/y^3
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\[\frac{ \frac{ 4y+1 }{ 9y ^{4} } }{ \frac{ y+2 }{ y ^{3} } }=\frac{ 4y+1 }{ 9y ^{4} }\div \frac{ y+2 }{ y ^{3} }\] If you know how to do a normal division of fractions, then maybe that makes more sense?
yes
\[\frac{ 4y+1 }{ 9y^4 }\div \frac{ y+2 }{y^3 }\]
\[\frac{ 4y+1 }{ 9y^4 } \times \frac{ y^3 }{ y+2}\]
Yep, exactly. Did that help ya simplify it some?
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still trying
Alrighty, no worries :3
what is :3
Oh, its a smiley face xD If you look at it sideways, lol.
lol
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Yeah, my bad. Just let me know if you want me to work through it more or something.
will do
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