Question

I thought I was doing it right until I went to mark my answer and the answer I got was not there, so please help me
question 9squ7-squ28
I got for my answer 5qu7??

Answer 1

@phi

Answer 2

\[ 9 \sqrt{7} - \sqrt{28} \]
factor 28 into its prime factors, and pull out pairs
28= 2*14= 2*2*7
so
\[ \sqrt{28}= \sqrt{2\cdot 2 \cdot 7} \]
there is one pair of 2's we can take out (and put only 1 of them out front)
we get
\[ \sqrt{2\cdot 2 \cdot 7} = 2 \sqrt{7}\]

now your problem is
\[ 9 \sqrt{7} - 2\sqrt{7} \]

Answer 3

if you have 9 sqr(7) and take away 2 of them, how many sqr(7)'s do you have ?

Answer 4

it would be 7squ7 thank you I don't know what I wronge I have another that im stuck on too

Answer 5

please post it.