Question

What is the solution to the system of equations that contains −3x + y = 3 and 2x − y = −1?




no solution

(−1, 3)

infinite number of solutions

(−2, −3)

Answer 1

add the equations to eliminate y.

then solve for x

substitute x into either equation to find y

Answer 2

\(-3x+y=3\)
\(2x-y=-1\)

You would then add them together.

\(-3x+\cancel{y}=3\)
\(2x-\cancel{y}=-1\)
\(-x=2\rightarrow x=-2\)

You can then plug in that in one of the original equations.