Question

Could anyone help with this question:
[3*(4)^1/4]-[12*(2)^-3/2]
[it would read: 3 times 4 to the (1/4) minus 12 times 2 to the (-3/2)] Sorry about how messy it looks. I have to calculate this using the laws of exponents but I'm not sure where to start.

Answer 1

the answer is zero:

3*(4)^1/4]-[12*(2)^-3/2
3(4^1/4)=3sqrt(2) & 2^-3/2=12/sqrt(8)=12/2sqrt(2)=6/sqrt2=3sqrt2
and then we have
3sqrt2-3sqrt2=0