Find the area of the triangle B = 104°, a = 11 cm, c = 18 cm
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OpenStudy (nincompoop):
Area = (ac*sinC)/2
OpenStudy (anonymous):
very good nin.
OpenStudy (nincompoop):
did I interrupt what you were typing, @genius12 ?
sorry!
OpenStudy (anonymous):
no lol thats what i was typing except with a small explanation =P
OpenStudy (nincompoop):
oh yah I was going into details to show the relationship of that area formula with 1/2(bh)
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OpenStudy (nincompoop):
but I have to study for my test tomorrow :P you can do that part for me
medal in advanced!
OpenStudy (anonymous):
i'll wait until OP requests for an explanation lol.. @nincompoop
OpenStudy (anonymous):
in order to take the sin of C i have to find C. how do i do that?
OpenStudy (nincompoop):
my bad I meant sinB
OpenStudy (anonymous):
Oh okay. Thank you
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OpenStudy (anonymous):
B* is already given. it's 104°. The area of a generic triangle is given by the length of 2 sides and the angle between them multiplied by 1/2. Here we're given the sides 'a' and 'c' and the angle between them is B = 104°. So it's (1/2)(ac)sin(104°)