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Explain using pictures why the MID(1) and MID(2) approximations to this integral give the exact value. the integral is sin(theta)d(theta) between 0 and 2pi i know that the integral is 0.
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@timo86m
mid 1 mid 2?
yeah i have no idea....
i was hoping you would know:(
lol i know mid point :P lol i think its zero cuzz of something like this |dw:1378961030082:dw|
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wait the midpoint is 0? i know the integral is zero because if u graph sin(theta) they just cancel each other out on the graph
so will aproximations :D
|dw:1378961200486:dw|
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