I need help solving this rational equation
\[\sqrt{x+2} =x\]
I know you square both sides
So is it x+2 =X^2
It's a radical equation, not rational equation, but yes, after squaring both sides, rewrite in standard form, then use quadratic formula.
So \[X^2 -x-2?\]
Yes, and it looks factorable too.
*missing = 0
and, \(x \ne 2\)
? x=/=2 @rsadhvika
sorry was a typo, it shud be \(x \ne -2\)
Wolfram says the answer IS 2... http://www.wolframalpha.com/input/?i=find+solutions+to+sqrt+%28x%2B2%29+%3Dx
2 is one of the solutions.
ok it shud be \(x> -2\) :)
I meant to the quadratic, If you try the other one in the original equation though . . .
\(\bf \sqrt{x+2} =x \implies x + 2 = x^2 \implies 0 = x^2-x-2\\ \implies (x-\square?)(x+\square?)\)
or \(\bf (x-\square?)(x+\square?)=0 \) for that matter
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