Need geometry help
Read Euclid.
\[\angle RQS \] and \[\angle TQS\] are a linear pair where \[m \angle RQS=2x+4\] and \[m \angle TQS=6x+20\] 1. Solve for x. 2. FInd \[m \angle RQS\] and \[m \angle TQS\] 3. Show how you can check your answer.
if two angles x and y are a linear pair, then they are adjacent and supplementary so that means they add to 180 degrees ie x+y = 180
in this case, RQS and TQS are a linear pair, so that means (2x+4) + (6x+20) = 180 solve for x
tell me what you get
x=19.5?
now use this to find angles RQS and TQS
I'll do the first angle to show you what I mean
angle RQS=2x+4 angle RQS=2*19.5+4 ... replace x with 19.5 (since x = 19.5) angle RQS=39+4 angle RQS=43 degrees
I tried to do the one for angle TQS and this is what i got: angle TQS=6x+20 angle TQS=6*19.5+20 angle TQS=117+20 angle TQS=119 degrees
did i do it correct?
117 + 20 is NOT equal to 119
I can see how you got 119, you did 117+2
137 sorry
you got it
the check is to make sure they add to 180, and they do (angle RQS) + (angle TQS) (43) + (137) 43 + 137 180 so that checks out
Thank you for helping me :) Would you be able to guide me thru another question similar to what we just did?
sure I can do one more
Ok, great! :-) \[\angle RQS\] and \[\angle TQS \] are vertical angles where \[m \angle RQS=3(x+7) \] and \[m \angle TQS=4x+15\] 1. Solve for x. 2. Find \[m \angle RQS\] and \[m \angle TQS \] 3. Show how you can check your answer.
hint: vertical angles are congruent
would you be able to help me find x?
angle RQS = angle TQS 3(x+7) = 4x+15 3x + 21 = 4x + 15 solve for x
would x be 6?
correct
now use this to find angle RQS and angle TQS
angle RQS=3(x+7) angle RQS=3*6+7 angle RQS=18+7 angle RQS=25 degrees angle TQS=4x+15 angle TQS=4*6+15 angle TQS=24+15 angle TQS=39 degrees
angle RQS=3(x+7) angle RQS=3(6+7) angle RQS=3(13) angle RQS=39
TQS is correct
Thank you so much for your help :)
you're welcome
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