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A line has a slope of -3 and passes through the point (5, -1). What is the equation of the line?
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which form?
you would use the y=mx=b formula and plus in the (-5,1) so you would write -1=-3(5)+b and solve for b. so for b you would get 14. so now your formula would be y=-3x+14!
we have to use point slope form y-y1=m(x-x1) where our slope is m=-3 and our point is (5,-1) = (x1,y1) so x1=5 and y1=1 all you have to do is plug in x1 y1 and m into y-y1=m(x-x1)
would it be positive 3...
point slope form: y + 1 = -3(x-5)
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if the slope is -3 then the m would be -3. thats how i do it I'm not sure how your teacher wants
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