x-1/x as x approaches 0
\[\lim_{x \rightarrow 0}\frac{ x-1 }{x} = \] knowing that we can't divide by 0, the limit would be an indetermination.
But wouldnt it be infinite since o approaches 0
Wrong, this is not an indeterminate form: \[ \frac {-1}0 \]We know that this is undefined!
Consider \[ x\times 0=-1 \]It is not like \[ x\times 0=0 \]
In the first equation, there is NO defined number that could be a solution for \(x\). Hence undefined. In the second equation there a many possible solutions for \(x\) and we don't have the context to determine which is correct. Hence indeterminate.
This limit does not exist. It can approach \(-\infty\) or \(\infty\) depending which side you come from.
Nicely said @wio
oh got it but the beginning was kind of unclear but thanks
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