Choose the slope-intercept equation of the line that passes through the point (-5, -1) and is perpendicular to y = five halves x + 2.

y = two fifths x + 1

y = -five halves x - 27 halves

y = -two fifths x - 3

y = five halves x + 23 halves
PLEASE HELP

Question

Choose the slope-intercept equation of the line that passes through the point (-5, -1) and is perpendicular to y = five halves x + 2.

y = two fifths x + 1

 y = -five halves x - 27 halves

 y = -two fifths x - 3

 y = five halves x + 23 halves
PLEASE HELP

jdoe0001 · Answer

what is the slope of $\bf y = \cfrac{5}{2}x + 2 \quad ? $

anonymous · Answer

5/2

jdoe0001 · Answer

yes, 5/2
so a line that's perpendicular to that equation, will have a NEGATIVE RECIPROCAL slope
what does that mean?
well
RECIPROCAL of 5/2
2/5

NEGATIVE of that
-2/5

so, now we know that, the line has a slope of -2/5 and passes through the point (-5, -1)
so, we'll plug those values in your "point-slope form" of $\bf y-y_1=m(x-x_1)$

so $\large \begin{array}{llll}
&x_1&y_1&\qquad slope = -\cfrac{2}{5}\
(&-5, & -1)\\quad \\quad \
&&&\color{blue}{y-y_1=m(x-x_1)}
\end{array} $

goformit100 · Answer

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