How to find Secant lines if point P(6,-2) lies on a curve y=2/(5-x) If Q is the point (x,2/(5-x)) and find the slope of mPQ

Question

anonymous · Answer

The slope of a function between two points is
$$\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}~~?$$
In this case, $(x_1,y_1)=(6,-2)$ and  $(x_2,y_2)=\left(x,\dfrac{2}{5-x}\right)$

Plug these coordinates in and see if you can simplify it.

venomblast · Answer

Ohh o. the (x, 2/(5-x) ) confused me

anonymous · Answer

typo there 
$$\large \frac{\frac{2}{5-x}+2}{x-6}$$

venomblast · Answer

ok

anonymous · Answer

might be easiest algebra if you multiply top and bottom by $5-x$
leave the denominator in factored form

venomblast · Answer

i thought it was $$d1-d2/t1-t2$$

anonymous · Answer

it is

anonymous · Answer

$$y_1=\frac{2}{5-x}, y_2=-2, x_1=x, x_2=6$$

venomblast · Answer

so is it reverse?

venomblast · Answer

will i get this -2x+12/x-6

venomblast · Answer

im confused