Question

How to find Secant lines if point P(6,-2) lies on a curve y=2/(5-x) If Q is the point (x,2/(5-x)) and find the slope of mPQ

Answer 1

The slope of a function between two points is
\[\frac{\Delta y}{\Delta x}=\frac{y_2-y_1}{x_2-x_1}~~?\]
In this case, \((x_1,y_1)=(6,-2)\) and \((x_2,y_2)=\left(x,\dfrac{2}{5-x}\right)\)

Plug these coordinates in and see if you can simplify it.

Answer 2

Ohh o. the (x, 2/(5-x) ) confused me

Answer 3

typo there
\[\large \frac{\frac{2}{5-x}+2}{x-6}\]

Answer 4

ok

Answer 5

might be easiest algebra if you multiply top and bottom by \(5-x\)
leave the denominator in factored form

Answer 6

i thought it was \[d1-d2/t1-t2\]

Answer 7

it is

Answer 8

\[y_1=\frac{2}{5-x}, y_2=-2, x_1=x, x_2=6\]

Answer 9

so is it reverse?

Answer 10

will i get this -2x+12/x-6

Answer 11

im confused